1 - (у-2) в кубе

1 - (y-2) ^3 = (1 - (y-2)) * (1+y-2 + (y-2) ^2) = (1-y+2) * (y-1+y^2-4y+4) = (3-y) * (y^2-3y+3)

выполним проверку:

(3-y) * (y^2-3y+3) = 3 * (y^2 - 3y + 3) - y * (y^2 - 3y + 3) = (3*y^2 - 3*3y + 3*3) - (y*y^2 - y*3y + y*3) = 3y^2-9y+9-y^3+3y^2-3y = 1 - (y^3+12y-6y^2-8) = 1 - (y-2) ^3

Ответ : (3-y) * (y^2-3y+3)