решить уравнение 2x^3+5x^2-4x-3=0

2x^3 + 5x^2 - 4x - 3 = 0

2 х^3 - 2x^2 + 7x^2 - 7x + 3x - 3 = 0

2x^2 (x - 1) + 7x (x - 1) 3 (x - 1) = 0

(x - 1) (2x^2 + 7x + 3) = 0

(x - 1) (2x^2 + 6x + x + 3) = 0

(x - 1) (2x (x + 3) + x + 3) = 0

(x - 1) (x + 3) (2x + 1) = 0

x = 1

x = - 3

x = - 1/2 = 0,5