Найти f' (0) и f' (2), если:f (x) = x³-2xf (x) = x²+x+1

1) f (x) = x³ - 2x, найдем производную;

f ' (х) = 3 х² - 2;

f ' (0) = 3 * 0² - 2 = 3 * 0 - 2 = 0 - 2 = - 2;

f ' (2) = 3 * 2² - 2 = 3 * 4 - 2 = 12 - 2 = 10.

2) f (x) = x² + x + 1, аналогично;

f ' (х) = 2 х + 1;

f ' (0) = 2 * 0 + 1 = 0 + 1 = 1;

f ' (2) = 2 * 2 + 1 = 4 + 1 = 5.