1 4/9+3 2/7, 6 7/12+4 31/48, 7+1 29/40+2 17/30, 2 1/25+5/6+1 11/75, 3 11/35+4 1/56, 9/17+2 3/8

Question

Александр Григорьев

Математика

25 декабря, 19:45

1 4/9+3 2/7, 6 7/12+4 31/48, 7+1 29/40+2 17/30, 2 1/25+5/6+1 11/75, 3 11/35+4 1/56, 9/17+2 3/8

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Юджи · Answer 1

1 4/9 + 3 2/7 = (1 * 9 + 4) / 9 + (3 * 7 + 2) / 7 = 13 / 9 + 23 / 7 = (91 + 207) / 63 = 298 / 63 =

= 4 46/63;

6 7/12 + 4 31/48 = (6 * 12 + 7) / 12 + (4 * 48 + 31) / 48 = 79/12 + 223/48 = ((79 * 4) + 223) / 48 = 539/48 = 11 11/48;

7 + 1 29/40 + 2 17/30 = 7 + (1 * 40 + 29) / 40 + (2 * 30 + 17) / 30 = 7 / 1 + 69 / 40 + 77 / 30 = (7 * 120 + 69 * 3 + 77 * 4) / 120 = (840 + 207 + 308) / 120 = 1355 / 120 = 11 35/120;

2 1/25 + 5/6 + 1 11/75 = (2 * 25+1) / 25 + 5/6 + (1 * 75 + 11) / 75 = 51/25 + 5/6 + 86/75 = (51 * 6 + 25 * 5 + 86 * 2) / 150 = (306 + 125 + 172) / 150 = 603/150 = 4 3/150 = 4 1/50;

3 11/35 + 4 1/56 = (3 * 35 + 11) / 35 + (4 * 56 + 1) / 56 = 116/35 + 225/56 = (116 * 8 + 225 * 5) / 280 = (928 + 1125) / 280 = 2053/280 = 7 93/280;

9/17 + 2 3/8 = 9/17 + (2 * 8 + 3) / 8 = 9/17 + 19/8 = (9 * 8 + 19 * 17) / 136 = (72 + 323) / 136 = 395/136 = 2 123/136.