1) f (x) = tgx-2sinx x=π/4 2) f (x) = 6sinx+tgx x=π/6

1). f (x) = tgx - 2sinx,

x = π/4,

tgx - 2sinx = tg π/4 - 2sin π/4 = 1 - 2 * 1/√2 = 1 - 2/√2 = (√2 - 2) / √2.

f (x) = 1 - 2/√2.

2). f (x) = 6sinx + tgx,

x = π/6,

6sinx + tgx = 6sin π/6 + tg π/6 = 6 * 1/2 + 1/√3 = 6/2 + 1/√3 = 3 + 1/√3 = (3√3 + 1) / √3.

f (x) = 3 + 1/√3.

Ответ: 1). f (x) = 1 - 2/√2; 2). f (x) = 3 + 1/√3.