Упростите выражение: (b3-b2) (b3+b2) - (1+b2) (1-b2) (1-b2+b4) И найдите его числовое значение если b=0,1

(b³ - b²) ⋅ (b³ + b²) - (1 + b²) ⋅ (1 - b²) ⋅ (1 - b² + b⁴) =

b³ ⋅ (b³ + b²) - b² ⋅ (b³ + b²) - (1 ⋅ (1 - b²) - b² ⋅ (1 - b²)) ⋅ (1 - b² + b⁴) =

b⁶ + b⁵ - b⁵ - b⁴ - (1 - b² - b² + b⁴) ⋅ (1 - b² + b⁴) =

b⁶ - b⁴ - (1 - b² - b² + b⁴) + (1 - b² - b² + b⁴) ⋅ b² - (1 - b² - b² + b⁴) ⋅ b⁴ =

b⁶ - b⁴ - 1 + b² + b² - b⁴ + b² - b⁴ - b⁴ + b⁶ - b⁴ + b⁶ + b⁶ - b ⁸ =

b⁶ + b⁶ + b⁶ + b⁶ - b⁴ - b⁴ - b⁴ - b⁴ - b⁴ + b² + b² + b² - b⁸ - 1 =

4 ⋅ b⁶ - 5 ⋅ b⁴ + 3 ⋅ b² - b⁸ - 1.

Если b = 0,1, то 4 ⋅ b⁶ - 5 ⋅ b⁴ + 3 ⋅ b² - b⁸ - 1 = 4 ⋅ 0,1⁶ - 5 ⋅ 0,1⁴ + 3 ⋅ 0,1² - 0,1⁸ - 1 = 4 ⋅ 0,000001 - 5 ⋅ 0,00001 + 3 ⋅ 0,01 - 0,00000001 - 1 = 0,000004 - 0,00005 + 0,03 - 0,00000001 - 1 = - 0,97004601.