Решить уравнение: А) х (5+х) (х-5) - (х-3) (х^2+3 х+9) = -23 Б) (2x-3) ^2-4 (x-1) (x+2) = -2

А) х (5 + х) (х - 5) - (х - 3) (х^2 + 3 х + 9) = - 23

х (x + 5) (х - 5) - (х - 3) (х^2 + 3 х + 3^2) = - 23

х (x^2 - 25) - (х^3 - 3^3) = - 23

(x^3 - 25x) - (х^3 - 27) = - 23

x^3 - 25x - х^3 + 27 = - 23

x^3 - х^3 - 25x = - 23 - 27

-25x = - 50

x = - 50 / (-25)

x = 2

Ответ: 2.

Б) (2x - 3) ^2 - 4 (x - 1) (x + 2) = - 2

(4x^2 - 12x + 9) - 4 (x^2 - x + 2x - 2) = - 2

4x^2 - 12x + 9 - 4 (x^2 + x - 2) = - 2

4x^2 - 12x + 9 - 4x^2 - 4x + 8 = - 2

4x^2 - 4x^2 - 12x - 4x + 9 + 8 = - 2

-16x + 17 = - 2

-16x = - 2 - 17

-16x = - 19

x = - 19 / (-16)

x = 19/16

x = 1 3/16

Ответ: 1 3/16.