Вычислите 5/8 - (1/3+1/6).16/21 - (1/6+2/7).7/8 - (1/4+2/5

Question

Георгий Михайлов

Математика

6 ноября, 16:37

Вычислите 5/8 - (1/3+1/6).16/21 - (1/6+2/7).7/8 - (1/4+2/5

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Владислава Дубинина · Answer 1

1) 5/8 - (1/З + 1/6) = 5/8 - ((1 * 2) / (З * 2) + 1/6) = 5/8 - (2/6 + 1/6) = 5/8 - (2 + 1) / 6 = 5/8 - З/6 = 5/8 - 1/2 = 5/8 - (1 * 4) / (2 * 4) = 5/8 - 4/8 = (5 - 4) / 8 = 1/8.

2) 16/21 - (1/6 + 2/7) = 16/21 - ((1 * 7) / (6 * 7) + (2 * 6) / (7 * 6)) = 16/21 - (7/42 + 12/42) = 16/21 - 19/42 = (2 * 16) / (2 * 21) - 19/42 = 32/42 - 19/42 = 13/42.

3) 7/8 - (1/4 + 2/5) = 7/8 - ((1 * 5) / (4 * 5) + (2 * 4) / (5 * 4)) = 7/8 - (5/2O + 8/2O) = 7/8 - 13/2O = (7 * 5) / (8 * 5) - (13 * 2) / 4O = 35/4O - 26/4O = 9/4O.