Найти корни уравнения 4 х^2-547 х+543=0

4x^2 - 547x + 543 = 0;

D = b^2 - 4ac;

D = (-547) ^2 - 4 * 4 * 543 = 299209 - 8688 = 290521; √D = 539;

x = (-b ± √D) / (2a);

x1 = ( - (-547) + 539) / (2 * 4) = (547 + 539) / 8 = 1086/8 = 135,75;

x2 = ( - (-547) - 539) / (2 * 4) = (547 - 539) / 8 = 8/8 = 1.

Ответ. 1; 135,75.