1) tg2x=1 / (под корнем) 3 2) tg (-x) = 1 3) cosx/3=1/2 Все в обычных дробях

1) tg (2x) = 1 / √3;

2x = arctg (1 / √3) + - π * n, где n - натуральное число;

2x = π/6 + - π * n;

x = π/12 + - π/2 * n.

2) tg (-x) = 1;

- x = arctg (1) + - π * n;

- x = √2/2 + - π * n;

x = - √2/2 + - π * n.

3) cos (x/3) = 1/2;

x/3 = arccos (1/2) + - 2 * π * n;

x/3 = π/3 + - 2 * π * n;

x = π + - 6 * π * n;