Приведите уравнениe к виду ax²+bx+c=0 1) (2x-1) (2x+1) = x (2x+3) 2) (x+1) (x+2) = (2x-1) (x-2) 3) (x+3) (3x-2) = (4x+5) (2x-3)

ax²+bx+c=0

1) (2x - 1) (2x + 1) = x (2x + 3);

(2x) ^2 - 1^2 = 2x^2 + 3x;

4x^2 - 1 - 2x^2 - 3x = 0;

2x^2 - 3x - 1 = 0;

2) (x + 1) (x + 2) = (2x - 1) (x - 2);

x^2 + 2x + x + 2 = 2x^2 - 4x - x + 2;

x^2 - 2x^2 + 3x + 2 + 5x - 2 = 0;

-x^2 + 8x + 0 = 0;

x^2 - 8x + 0 = 0;

3) (x + 3) (3x - 2) = (4x + 5) (2x - 3);

3x^2 - 2x + 9x - 6 = 8x^2 - 12x + 10x - 15;

3x^2 + 7x - 6 = 8x^2 - 2x - 15;

3x^2 - 8x^2 + 7x + 2x - 6 + 15 = 0;

-5x^2 + 9x + 9 = 0;

5x^2 - 9x - 9 = 0.