Решите уравнения 12x^2 - (4x-3) (3x+1) = -2, (4x-3) (3+4x) - 2x (8x-1) = 0, X + (5x+2) ^2=25 (1+x^2) : ^2 - во второй степени.

1) 12 х^2 - (4 х - 3) * (3 х + 1) = - 2;

12 х^2 - (4 х * 3 х + 4 х * 1 - 3 * 3 х - 3 * 1) = - 2;

12 х^2 - (12 х^2 + 4 х - 9 х - 3) = - 2;

12 х^2 - 12 х - 4 х + 9 х + 3 = - 2;

5 х = - 2 - 3;

5 х = - 5;

х = - 5 : 5;

х = - 1.

2) (4 х - 3) * (3 + 4 х) - 2 х * (8 х - 1) = 0;

(4 х - 3) * (4 х + 3) - 2 х * 8 х - 2 х * (-1) = 0;

16 х^2 - 9 - 16 х^2 + 2 х = 0;

2 х = 9;

х = 9 : 2;

х = 4 1/2.

3) х + (5 х + 2) ^2 = 25 * (1 + х^2);

х + 25 х^2 + 2 * 5 х * 2 + 4 = 25 * 1 + 25 * х^2;

х + 25 х^2 + 20 х + 4 = 25 + 25 х^2;

25 х^2 - 25 х^2 + х + 20 х = 25 - 4;

21 х = 21;

х = 21 : 21;

х = 1.