1) sin (2x-п/3) + 1=0 2) 2 sin x-1=0

1) sin (2x - π/3) + 1 = 0;

sin (2x - π/3) = - 1;

2x - π/3 = arcsin (-1) + - 2 * π * n, где n - натуральное число;

2x - π/3 = - π/2 + - 2 * π * n;

2x = - 2π/3 + - 2 * π * n;

x = - π/3 + - π * n.

2) 2sin (x) - 1 = 0;

2sin (x) = 1;

sin (x) = 1/2;

x = arcsin (1/2) + - 2 * π * n;

x = π/6 + - 2 * π * n.