Найти корень уравнения: 1/3y+2=1; 1/5x+11=1-3/5x; 8-1/4z=1; 3-5/7t=1-3/7t; 1/8u-2=5/8u+1; 2/5z-7=3

Question

Надежда Сорокина

Математика

5 марта, 21:42

Найти корень уравнения: 1/3y+2=1; 1/5x+11=1-3/5x; 8-1/4z=1; 3-5/7t=1-3/7t; 1/8u-2=5/8u+1; 2/5z-7=3

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Амина Панкратова · Answer 1

1. Умножим обе части на 3y:

1/3y + 2 = 1; 1 + 2 * 3y = 3y; 6y - 3y = - 1; 3y = - 1; y = - 1/3.

2.

1/5x + 11 = 1 - 3/5x; 1/5x + 3/5x = 1 - 11; 4/5x = - 10; 4 = - 10 * 5x; 4 = - 50x; x = - 4/50 = - 2/25.

3.

8 - 1/4z = 1; 8 - 1 = 1/4z; 7 = 1/4z; 7 * 4z = 1; 28z = 1; z = 1/28.

4.

3 - 5/7t = 1 - 3/7t; 3 - 1 = 5/7t - 3/7t; 2 = 2/7t; 1 = 1/7t; 7t = 1; t = 1/7.

5.

1/8u - 2 = 5/8u + 1; - 2 - 1 = 5/8u - 1/8u; - 3 = 4/8u; - 3 = 1/2u; - 3 * 2u = 1; - 6u = 1; u = - 1/6.

6.

2/5z - 7 = 3; 2/5z = 3 + 7; 2/5z = 10; 2 = 10 * 5z; 2 = 50z; z = 2/50 = 1/25.