функция 1) f (x) = 2 х^2. 2) f (x) = 2x^2 + 3 х - 4. 3) f (x) = х^2-9/x+3 найти значение f (-2); f (1/3); f (1)

1. f (x) = 2 * х^2;

f (-2) = 2 * (-2) ^2 = 2 * 4 = 8;

f (1/3) = 2 * (1/3) ^2 = 2 * 1/9 = 2/9;

f (1) = 2 * 1^2 = 2 * 1 = 2;

2. f (x) = 2 * x^2 + 3 * х - 4;

f (-2) = 2 * (-2) ^2 + 3 * (-2) - 4 = 8 - 6 - 4 = - 2;

f (1/3) = 2 * (1/3) ^2 + 3 * 1/3 - 4 = 2 * 1/9 + 1 - 4 = 2/9 - 3 = (2 - 27) / 9 = - 25/9 = - 2*7/9;

f (1) = 2 * 1^2 + 3 * 1 - 4 = 2 + 3 - 4 = 1;

3. f (x) = х^2 - 9/x + 3;

f (-2) = (-2) ^2 - 9 / (-2) + 3 = 4 + 4,5 + 3 = 11,5;

f (1/3) = (1/3) ^2 - 9 / (1/3) + 3 = 1/9 - 27 + 3 = 1/9 - 24 = - 215/24 = - 8 * 23/24;

f (1) = 1^2 - 9/1 + 3 = 1 - 9 + 3 = - 5.