Решите систему уравнений методом алгебраического сложения x²-y²=4 2x²+y²=104

(x^2 + 2x^2) + ( - y^2 + y^2) = 4 + 104;

3x^2 = 108;

x^2 = 108 : 3;

x^2 = 36;

x1 = 6 или х2 = - 6.

6^2 - y^2 = 4;

36 - y^2 = 4;

y^2 = 36 - 4;

y^2 = 32;

y = √16 * 2;

y1 = 4√2;

y2 = - 4√2;

( - 6) ^2 - y^2 = 4;

36 - y^2 = 4;

y^2 = 36 - 4;

y^2 = 32;

y = √16 * 2;

y3 = 4√2;

y4 = - 4√2;

Ответ: х1 = 6, х2 = - 6, у1 = 4√2, у2 = - 4√2, у3 = 4√2, у4 = - 4√2.