1) y=cos^3 (lnx) 2) y=√sin (4x^2) 3) y=2^x*tg (x-x^2) Требуется взять производную 1) y=sin (tgx) 2) y=√tg (5x^2) 3) y = 7^x*ctg (3x^2)

1) y' = (cos^3 (ln (x))) = 3 * cos^2 (ln (x)) * (-sin (ln (x)) * 1/x;

2) y' = (√sin (4x^2)) ' = 1/2 * sin^ (-1/2) (4x^2) * cos (4x^2) * 8x;

3) (y) ' = (2^x * tg (x - x^2)) ' = (2^x) ' * tg (x - x^2) + 2^x * (tg (x - x^2)) ' = 2^x * ln (2) * tg (x - x^2) + 2^x * 1 / cos^ (x - x^2) * (1 - 2x).

1) (y) ' = cos (tg (x)) * 1 / cos^2 (x);

2) (y) ' = 1/2 * (tg (5x^2)) ^ (-1/2) * 1 / cos^2 (5x^2) * 10x;

3) (y) ' = (7^x * ctg (3x^2)) ' = (7^x) ' * ctg (3x^2) + 7^x * (ctg (3x^2)) ' = 7^x * ln (7) * ctg (3x^2) + 7^x * (-1 / sin^2 (3x^2) * 6x.