3 + 2 log x+1 3 = 2 log 3 x+1

3 + 2 log (x + 1) 3 = 2 log (3) (x + 1);

3log (3) 3 + 2/log (3) x + 1 = 2log (3) x + 1;

(3log (3) 3 * log (3) (x + 1) + 2log (3) 3) / (log (3) (x + 1)) = 2log (3) (x + 1);

2log (3) ^2 (x + 1) = 3log (3) (x + 1) + 2;

log (3) (x + 1) = t;

2t^2 - 3t - 2 = 0;

D = 9 + 16 = 25;

t = (3 + - 5) / 4;

t = 2, t = - 1/2;

log (3) (x + 1) = 2;

3^2 = x + 1;

9 = x + 1;

x = 8;

log (3) (x + 1) = - 1/2;

3^-1/2 = x + 1;

1/sqrt3 = x + 1;

x = sqrt3/3 - 1 = (sqrt3 - 3) / 3.