Cos (2x-1) = -v2/2 Tgп/x=7 Sin2x=П/4 Ctgx=tgп/3

1) cos (2x - 1) = - √2/2;

2x - 1 = arccos (-√2/2) + - 2 * π * n, где n - натуральное число;

2x = - π/4 + 1 + - 2 * π * n;

x = - π/8 + 1/2 + - π * n.

2) tg (π/x) = 7;

π/x = arctg (7) + - π * n;

1/x = arctg (7) / π + - n;

x = 1 / (arctg (7) / π + - n).

3) sin (2x) = π/4;

2x = arcsin (π/4) + - 2 * π * n;

x = √2 / 4 + - π * n.

4) Так как tg (π/3) = √3, получим уравнение:

ctg (x) = √3;

x = arcctg (√3) + - π * n;

x = π/6 + - π * n.